Physics, asked by doctormaha01abcd, 1 year ago

How is Resistance is directly proportional to L^2 and inversely proportional to mass

Dhinu: but... how ?

Dhinu: wrute the equation of Resustance in terms of Rho , density , mass and length ... then you'll observe that resistance is inversely proportional to mass and directly proportional to the square of it's length

Dhinu: write*

omkar3rulzpatg3q: it is directly proportional to length not length square

Dhinu: it is if you write it in terms of rho , length and area ... but if you write d(density) = (A x l )/m (area x length / mass) .. then you'll observe that

omkar3rulzpatg3q: ok

Dhinu: yeah! try it ...

omkar3rulzpatg3q: but where will you substitute for density

Dhinu: in denominator

Dhinu: multiply numerator and denominator by l x m . (length x mass) then write (A x l )/m = d (density) .. and density is constant .. and then you'll observe that resistance is directly proportional to l^2 / m (square of length divided by m )

Answers

Answered by omkar3rulzpatg3q

I can help you with answer regarding mass
density
$= mass \div volume$
hence on re-arranging this we get that volume is directly proportional to mass
Hence when mass increases volume increases
As volume increases electrons get more space to move hence resistance decreases.hence resistance is inversely proportional to mass

Now regarding length
as per my knowledge I know that resistance is directly proportional to
${l}^{1}$
and not length square

doctormaha01abcd: but in the book ,it is given like that only

Answered by BrainlyHeart751

If the current is held constant, while the resistance varies, then Power = V^2 / R, so power is then proportional to 1/R i.e. inversely proportional to R, so you might say resistance is inversely proportional to power.

hope it helps u mark as brainliest please

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