Question

the interior angle of a regular polygon exceeds its exterior angle by 108 degree how many sides does a polygon have.

Answer 1

Answer:

10

Step-by-step explanation:

Let the exterior angle be x

we are given that the interior angle of a regular polygon exceeds its exterior angle by 108

So, interior angle = x+108

Since we know that the sum of interior angle and exterior angle is 180°

So, $x+x+108=180$

$2x+108=180$

$2x=72$

$x=36$

Formula : $180 \times \frac{n-2}{n}=\text{interior angle}$

$180 \times \frac{n-2}{n}=36+108$

$n=10$

Hence a polygon has 10 sides .

Answer 2

Answer:

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