Question

How is sin omega t differentiation is equal to cos omega t by omega?

Answer 1

Answer:

Step-by-step explanation:

d/dt[sint]=cost

d/dt[wt]=wd/dt[t]+td/dt[w]

            =w+0[coz differentiation of constant is zero]

now,d/dt[sinwt]=d/dt[sinwt].d/dt[wt]

                         =coswt .w