Chemistry, asked by Prithika, 1 year ago

How is the angular momentum value (mvr=h/2 pi) in Bohrs atomic theory (postulates) calculated? Please explain it in an easy way.


tanishqsingh: What exactly do you want to know? How the formula was derived? Or its applications?

Answers

Answered by ankitkumar0102
12

Actually, angular momentum value (mvr=nh/2 pi) not h/2pi.Coming to the point, Firstly, this formula was not derived by anyone. It was observed by BOHR from an experiment. Later it was proved by Albert Einstein with the help of De Broglie Equation. According to de Broglie,

Wavelength(w) = h/mv       ---(I)

and from equation derived after de Broglie eqn:-

nw = 2 pi r       ---------------(II)

where n is number of wave, w is de Broglie wavelength, r is radius of shell.From equation I and II,

n(h/mv) = 2 pi r         (putting the value of w from eqn I to II)

After simplifying we get,

Angular Momentum = mvr = nh/2 pi

PROVED


tanishqsingh: Absolutely correct!! Well done(y)
ankitkumar0102: thanks tanishq
Similar questions