Question

how is the electric flux through a closed sphere of radius R changed if the charge at the centre is placed at a distance of R/2 from the surface of sphere?​

Answer 1

Answer:

According to the guass law the flux through the closed surface is given byϕ equals q over epsilon subscript 0

The flux due to enclosed charge does not depend on the shape and size of the surface. Therefore the flux would remain same.

(ii)

In case of dipole, net charge inside the closed surface is zero. Hence flux will be zero.

Explanation:

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