Question

How is
the electric flux
through a closed sphere of
radues R charged if the
charge
at the centre is placed
at a distance of P/2 from the
surface of sphere?​

Answer 1

We know that D=eE -(1)

, and E = q/(4πeR²). That is:-

eE=q/(4πR²) -(2)

Now, from (1) and (2):-

D=q/(4πR²)

Now, Distance=P/2

Radius=R

Therefore, P/2=q/{4×(22/7)×R²}

P/2=q/{(88/7)×R²}

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