Question

how is the law of conservation of matter verified in the experiment of calcium chloride and sodium sulphate

Answer 1

Explanation:

Law of conservation of mass: This law states that the total mass in a chemical reaction remains constant that is the total mass on the reactant side will be equal to the total mass on the product side in a chemical reaction.

Now, in a chemical reaction:

$CaCl_2(s)+Na_2SO_4(aq.)\rightarrow 2NaCl(aq.)+CaSO_4(aq.)$

$\text{Mass on reactant side}=\text{Mass of }CaCl_2+\text{Mass of }Na_2SO_4$

$\text{Mass of }CaCl_2=40+(2\times 35.5)=111amu$

$\text{Mass of }Na_2SO_4=(2\times 23)+32+(4\times 16)=142amu$

Mass of the reactant = 253 amu.

$\text{Mass on product side}=\text{Mass of }2NaCl+\text{Mass of }CaSO_4$

$\text{Mass of }2NaCl=2\times(23+35.5)=117amu$

$\text{Mass of }CaSO_4=40+32+(4\times 16)=136amu$

Mass of the product = 235 amu.

As ,the mass of reactant = Mass of product

Hence, this experiment verifies the law of conservation of mass.