How is the linear speed of a particle moving along a circular path related to its angular velocity???
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Answered by
47
Heya......!!!!
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Let :
( v ) => Linear Velocity .
( ω ) => Angular Velocity .
There is a realtion between linear displacement and angular displacement .
let angular displacement be ( x )
Angle which is moved by particle ( θ )
radius ( r )
=> θ = x / r
=> x = r θ .............( i )
in this equation ( i ) divide both side by ( t ) time
=> x / t = rθ/t
=> x / t. = v ,, θ/t. = ω
v = rω
Hence the realtion between angular velocity and linear velocity is :-
➡ ♦ v = r × ω ♦ .
===========================
Hope It Helps You ☺
_________________________________
Let :
( v ) => Linear Velocity .
( ω ) => Angular Velocity .
There is a realtion between linear displacement and angular displacement .
let angular displacement be ( x )
Angle which is moved by particle ( θ )
radius ( r )
=> θ = x / r
=> x = r θ .............( i )
in this equation ( i ) divide both side by ( t ) time
=> x / t = rθ/t
=> x / t. = v ,, θ/t. = ω
v = rω
Hence the realtion between angular velocity and linear velocity is :-
➡ ♦ v = r × ω ♦ .
===========================
Hope It Helps You ☺
rohit710:
if helpful then pls mark my answer as brainliest
Answered by
2
Answer:Hi mate here is your answer___________________________Explanation:
consider a particle moving with uniform circular motion in anticlockwise direction with Centre O and radius R the particle cover an Arc of length ∆t moving from A to B.....Hence the angular displacement is ∆Ø=∆s/rdividing both side by ∆t∆∅/∆t=1∆s/r∆tin the time interval ∆t be Infinitesimally small [∆t=0]thenlim ∆∅/∆t=1/r[lim ∆s/∆t]but lim ∆∅/∆t=w and lim ∆s/∆t=vtherefore w=v/rv=rwplease mark me brainleast and follow me as it take so much concentration to solve this
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