Chemistry, asked by flomogustine, 11 months ago

How is the rate of disappearance of ozone related to the rate of appearance of oxygen gas in the following equation :2O3(g)...3O2(g)?If the appearance of o2 in the reaction is 6.0*10^-5m/s at a particular instant, what is the value of the rate of disappearance of O3 at this same time?

Answers

Answered by tracker31
8

The answer is,

4 \times  {10}^{ - 5}  \:  \: ms {}^{ - 1}

The relation is also in the pic provided.

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Answered by 27swatikumari
0

Answer: The value of the rate of disappearance of O3 at this same time is 4 torr ​sec^{-1}.

Explanation:

If the appearance of o2 in the reaction is 6.0*10^-5m/s at a particular instant, the rate of disappearance of O3 at this same time is

Rate- -\frac{1}{2} Δ[O3]/Δt = \frac{1}{3} Δ[O2]/Δt

-Δ[O3]/Δt = \frac{2}{3} Δ[O2]/Δt

= \frac{2}{3} x 6 torr sec^{-1}

= 4 torr ​sec^{-1}

Hence, the value of the rate of disappearance of O3 at this same time is 4 torr ​sec^{-1}.

To know more about chemical kinetics from the given link

https://brainly.in/question/2124122

https://brainly.in/question/54358575

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