how is the resistance of a wire affected if its radius is doubled
Answers
Answered by
56
Hii There!!
Since, R= rhow×l / A
or , R = rhow × l/ πr2
=) Here, Resistance of a wire is inverself proportional to the area of cross-section.
So, when we double the radius, it will increase the cross-section of the wire four-times.
Hope it helps
#DK
Since, R= rhow×l / A
or , R = rhow × l/ πr2
=) Here, Resistance of a wire is inverself proportional to the area of cross-section.
So, when we double the radius, it will increase the cross-section of the wire four-times.
Hope it helps
#DK
jeevasiddarth:
pls answer my question also
Answered by
34
Resistance is given by:
R=ρ×l / A
ρ: Resistivity
l: length
A: Area
R∝ (A=πr²)
R∝
When radius is doubled, Resistance decreased 2² times which is 4.
Hence when radius is doubled resistance decreases 4 times
R=ρ×l / A
ρ: Resistivity
l: length
A: Area
R∝ (A=πr²)
R∝
When radius is doubled, Resistance decreased 2² times which is 4.
Hence when radius is doubled resistance decreases 4 times
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