Physics, asked by palakkoli, 1 year ago

how is the resistance of a wire affected if its radius is doubled

Answers

Answered by Khushi0511
56
Hii There!!

Since, R= rhow×l / A
or , R = rhow × l/ πr2

=) Here, Resistance of a wire is inverself proportional to the area of cross-section.

So, when we double the radius, it will increase the cross-section of the wire four-times.



Hope it helps
#DK


jeevasiddarth: pls answer my question also
jeevasiddarth: ya see in the newest questions
jeevasiddarth: to the right
jeevasiddarth: thnx .
Answered by vishagh
34
Resistance is given by:
R=ρ×l / A

ρ: Resistivity
l:  length
A: Area

R∝ \frac{1}{Area}            (A=πr²)
R \frac{1}{ r^{2} }

When radius is doubled, Resistance decreased 2² times which is 4.

Hence when radius is doubled resistance decreases 4 times 


vishagh: pi is a constant, we dont put constants while using proportionality symbol So :)
Nikitakri: Ooo
Nikitakri: and yaa one more question
vishagh: yes ??
Nikitakri: if we doubled the radius then the resistance will be increased.. n bcoz 2²=4 Sooo
vishagh: since the relation is inversly proportional (1/x), when radius increase, resistance decreses. and that to by a squared value, so when radius is incresed 2 times , resistance decreses four times :)
Nikitakri: Oooo thank you sooo much
palakkoli: hi
palakkoli: so sweet of you
vishagh: welcom. pleasure helping u :)
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