Question

how is the sum of powers of 2 from 0 to infinity equal to -1 . If the answer is not known don't send anything ​

Answer 1

Answer:

2^0 + 2^1 + 2^2 + ... + 2^infinity is odd as all numbers except 2^0 contains the number 2 as a prime factor.

The above sum is the infinite sum of a geometric progression.

Therefore,

S = 1/(1-2) ( because sum of an infinite geometric progression of the form B, Br, Br^2, ...... is S n = B/(1-r).)

S = 1/(-1)

S = -1

Hence proved.