How is the time period of a simple pendulum affected if at all the following situations:
1)the length is made 4 times
2)the acceleration due to gravity is reduced to 1/4
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we calculate the time period by this formula
T=2π√l/g
so, if we change the value of lengt(L) and gravity the time effected ..
if the length is increase 4 time the time period is increase by 2 times because of square root.
and if gravity is decrease by ¼th the time period increase by 2 times.
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T=2π√l/g
so, if we change the value of lengt(L) and gravity the time effected ..
if the length is increase 4 time the time period is increase by 2 times because of square root.
and if gravity is decrease by ¼th the time period increase by 2 times.
if it is useful for you then please mark me...........
gouravsonu619:
Show the numerical problem on gravity part
How it happens
the length increase by 2 times because under root of 4 is 2
sorrry the time period increase 2 times and length by 4
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