Question

How is the two-point function of an operator dual to a scalar ADS field obtained in ADS/CFT?

Answer 1

The two point function of an operator dual to a scalar field in ADS/CFT can obtained directly from computation of the

Answer 2

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✔️✔️The procedure is shown in many papers and it is a common point to say that the only non-trivial contribution comes from non-polynomial terms in the momentum, and everyone arrives at the following integral (up to constants):

⟨O(x¯1)O(y¯1)⟩=∫d4p1¯(2π)4|p1|2νlog(|p1|ϵ)e−ip¯1(x¯1−y¯1)⟨O(x¯1)O(y¯1)⟩=∫d4p1¯(2π)4|p1|2νlog⁡(|p1|ϵ)e−ip¯1(x¯1−y¯1)

and suddenly the result of the two point function. 


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