Physics, asked by Anonymous, 1 year ago

how is value of constant G calculated??

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Answered by rohitkumargupta
4
Hello dear,
Cavendish's apparatus for experimentally determining the value of G involved a light, rigid rod about 2-feet long. Two small lead spheres were attached to the ends of the rod and the rod was suspended by a thin wire. When the rod becomes twisted, the torsion of the wire begins to exert a torsional force that is proportional to the angle of rotation of the rod. The more twist of the wire, the more the system pushes backwards to restore itself towards the original position. Cavendish had calibrated his instrument to determine the relationship between the angle of rotation and the amount of torsional force. A diagram of the apparatus is shown below.
Cavendish then brought two large lead spheres near the smaller spheres attached to the rod. Since all masses attract, the large spheres exerted a gravitational force upon the smaller spheres and twisted the rod a measurable amount. Once the torsional force balanced the gravitational force, the rod and spheres came to rest and Cavendish was able to determine the gravitational force of attraction between the masses. By measuring m1,m2,dm1,m2,d andFgravFgrav, the value of G could be determined. Cavendish's measurements resulted in an experimentally determined value of 6.75×10−116.75×10−11 N m22/kg22. Today, the currently accepted value is 6.672596.67259××10−1110−11N m22/kg2.

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