Question

How long does it take a current of 10mA to deliver 30C of current?

Answer 1

Answer:

3000 secs

Explanation:

Here,

$Q=30C \\ I=10mA \\ =10 \times {10}^{ - 3}m A \\ = {10}^{ - 2} mA$

Now, we know

$I = \frac{Q} {t} \\ t = \frac{Q} {I} \\ t = \frac{30}{ {10}^{ - 2} } \\ t = 30 \times {10}^{2} \\ t = 3000 \: secs$

Mark me brainliest. If you understand it.