Question

Two wires of same length and area made of two materials of resistivity ρ1 and ρ2 are connected in series to a source of potential V. The equivalent resistivity for the same area is * ρ = (ρ1 + ρ2) /2 ρ = (ρ1 x ρ2) /ρ1 + ρ2 ρ = (ρ1 + ρ2) /ρ1 x ρ2 ρ = ρ1 + ρ2 answer this the best answer will be marked as brainliest

Answer 1

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Answer 2

When two wires of the same length made of two materials of resistivity ρ1 and ρ2 are connected in series to a source of potential V, then the equivalent resistivity for the combination is 2(ρ1ρ2)ρ1+ρ2. Hence, the equivalent resistivity for the combination is 2(ρ1ρ2)ρ1+ρ2.

Inductance:

• Self-inductance is the possessions of the current-winning coil that oppose or opposes the change of current abounding through it.

• This happens for the most part on account of the self-persuaded emf created in the coil itself. In natural agreements, we can still mention that self-inductance is a wonder place skilled is the initiation of a service in a current-moving strand.

• The self-persuaded emf present in the coil will withstand the rise of current when the current increases and it will likewise oppose the fall of current if the current decreases. In essence, the course of the persuaded emf is opposite to the used strength if the current is growing and the route of the persuaded emf is aligned as the used generated power if the current is dropping.

• The above characteristic of the coil survives only for the changeful current that is the altering current and other than the direct or stable current. Self-inductance is continually antagonistic the changeful current and is calculated in Henry (SI whole).

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