Question

rationalise the denominator 4/√7+√3​

Answer 1

Answer:

i hope the answer satisfies you

Answer 2

$\frac{4}{ \sqrt{7} + \sqrt{3} } \\ \\ :=> \: \frac{4}{ \sqrt{7} + \sqrt{3} } \: \times \frac{ \sqrt{7} - \sqrt{3} }{ \sqrt{7} - \sqrt{3} } \\ \\ :=> \: \frac{4( \sqrt{7} - \sqrt{3} )}{ {( \sqrt{7} )}^{2} - {( \sqrt{3}) }^{2} } \\ \\ :=> \: \frac{4( \sqrt{7} - \sqrt{3} )}{7 - 3} \\ \\ :=> \frac{4( \sqrt{7} - \sqrt{3} )}{4} \\ \\ 4 \: from \: the \: numerator \: and \: 4 \: from \: the \\ denominator \: will \: be \: divided \: with \: a \: result \\ \\final \: answer \: = \sqrt{7} - \sqrt{3} .$