How long will it take a car to go from 0 to 44 km/hr if they are accelerating at 5 km/hr^2?
Answers
Answer:
Answer :
\boxed{\textsf{\textbf{Time taken (t) = 8.8 hr}}}
Time taken (t) = 8.8 hr
★ Given :
Initial velocity (u) = 0 km/hr
Final velocity (v) = 44 km/hr
Acceleration (a) = 5 km/hr²
★ To Find :
Time taken (t) = ?
★ Step by step explaination :
By substituting value of u, v & a in the equation we get:
→ 44 = 0 + 5t
→ 44 = 5t
→ 5t = 44
→ t = 44/5
→ t = 8.8 hours
⛬ Time taken by the car is 8.8 hours.
Explanation:
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Answer:
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Explanation:
Vf = V0 + at
Where
Vf = final velocity
V0 = initial velocity
a = acceleration
So we have
44km / hr = 0 + (5km / hr^2) * a
44km / hr = (5km / hr^2) * a divide both sides by (5km / hr^2)
[ 44km / hr ]
__________ = a = [44/5] hr = 8.8 hrs
[ 5km / hr^2 ]