How long will it take an electric current of 0.15 A to deposit all the copper from 500ml of 0.05M copper sulphate solution.
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Explanation:
Zn
2+
+2e
−
⟶Zn
1 mole is deposited by 2×96500=193000C
The charge supplied = 0.965×10×60=579C
∴ Number of moles deposited =
193000
579
=0.003 moles
In 500ml, number of moles =
1000
500
×0.2=0.1 moles
∴ Moles remaining in the 500ml solution = 0.1−0.003=0.097 moles
∴ Molarity =
500
1000
×0.097=0.194M
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