Question

How long would it take Jesse with an acceleration of -2.50 m/s 2to bring his bicycle with an initial velocity of 13.5 m/s to a complete stop?

Answer 1

Answer:

Time taken is 5.4 seconds.

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Explanation:

Here,

$a = - 2.5 \: m {s}^{ - 2} \\ u = 13.5 \: m {s}^{ - 1} \\ v = 0 \: m {s}^{ - 1} \\ we \: have \\ v = u + at \\ = > 0 = 13.5 - 2.5t \\ = > 2.5t = 13.5 \\ = > t = \frac{13.5}{2.5} \\ = \frac{135}{25} \\ = 5.4$

So, t = 5.4 seconds