How many 176 ohm resistors are required to carry 5A on 220 volt line
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1/R=x×(1/76)
R=176/x
v/i=176/x
x=176×1/v
=176×5/220
=4
R=176/x
v/i=176/x
x=176×1/v
=176×5/220
=4
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