Question

How many 176 ohm resistors (in parallel) are required to carry 5A on a 220V line?

Answer 1

voltage= 220V
Current = 5A
Resistance= 44ohm
Resistance of 44ohm is required

we know resistance in parallel
if we have same resistors is
R = R'/n
where n is number of resistor used

Here R'= 176ohm and R is 44 ohm

n= R'/R = 176/44= 4
Number of resistors used = 4

Answer 2

4 Resistors are required

Step-by-step explanation:

Given:

Volts = 220 Volts

Current = 5 Ampere

Resistance of each resistor, R = 176 Ohms

No of resistors = n

We know that:

v = RpI

∴        $v = \frac{R}{n}I$                   $($∵ $\frac{1}{Rp} = n(\frac{1}{R})$

Taking N to the other side we get,

$n = \frac{RI}{V}$

$n = \frac{176 * 5}{220}$

$n = 4$

Therefore, 4 Resistors are required.