Question

if * is an operation such that for integers a and b we have a*b =a×b+(a×a+b×b) then find:
(i) (-3)*(-5) (ii) (-6)*2

Answer 1

Answer:

The required answer is (i) $49$ (ii) $28$

Step-by-step explanation:

Integer: It is a whole number that can be positive, negative, or zero and is not a fraction.

Given: * is an operation such that for integers $a$ and $b$ we have $a*b$=$a$× $b$+($a$×$a+b$×$b$)

So,

(i) Now for, we put a$=(-3)$ and b$=(-5)$

We have

$(-3)$∗$(-5)$=$(-3)$×$(-5)$+[$(-3)$×$(-3)+(-5)$×$(-5)$]

$=15+(9+25)$

$=15+34=49$

(ii) Similarly, $a=-6, b=2$

$(-6)$×$2$=$(-6)$×$2$+[$(-6)$×$(-6)$+$2$×$2$]

$=-12+(36+4)$

$=-12+40=28$

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