Question

How many 176 ohm resistors ( in parallel ) are required to carry 5A on 220 V line ?

Answer 1

Let n = number of resistors each of resistance R.


When these resistors are connected in parallel , net resistance ( R' ) is given by

1/R' = 1/R + 1/R + ........ Up to n = n/R or R' = R/n


Now,

I = V/R' = nV/R or n = IR/V = 5 × 176/220 = 4.

Answer 2

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