Question

How many 176 ohm resistors(in parallel) are required to carry 5 a on a 220 v lime?

Answer 1

let the no. of resistors = N

176/N = r.eq

by ohms law,

V= I× R

220 = 176/N× 5

N =176/(220/5)

= N = 4

Answer 2

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Let the total no. of resistors = x

Given,

I = 5 A

V = 220 V

According to Ohm’s law,

V = IR

R = V/ I = 220/5 = 44Ω

Now for x number of resistors of resistance 176 Ω, the equivalent resistance of the resistors connected in parallel is 44 Ω.

1/44 = 1/176 + 1/176 + 1/176 .....χ times

1/44 = x / 176

=> x = 176/ 44

=> x = 4

Therefore, 4 resistors of 176 Ω are required to draw the given amount of current.

I hope, this will help you___❤❤

Thank you

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