Question

How many 176 Ω resistors

(in parallel) are required to

carry 5 A on a 220 V line?​

Answer 1

Step-by-step explanation:

For x number of resistors of resistance 176 Ω,

Here Supply voltage, V = 220 V

Current, I = 5 A

Equivalent resistance of the combination = R, given as

R=176/x

From Ohm’s law,

V/I=R

x=176*5/220

x=4

∴four resistors of 176 Ω are required to draw the given amount of current.

Answer 2

voltage= 220V

Current = 5A

Resistance= 44ohm

Resistance of 44ohm is required

we know resistance in parallel

if we have same resistors is

R = R'/n

where n is number of resistor used

Here R'= 176ohm and R is 44 ohm

n= R'/R = 176/44= 4

Number of resistors used = 4