Question

How many 176Ω resistors (in parallel) are required to carry 5 A on a 220V line?

Answer 1

Here, I = 5A, V = 220 V.

Resistance required in the circuit, R = V/I = 220V/5A = 44 W, Resistance of each resistor, r = 176 W

If n resistors, each of resistance r, are connected in parallel to get the required resistance R, then R = r/n    or n  = r/R   = 176/44 = 4

Answer 2

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Let the total no. of resistors = x

Given,

I = 5 A

V = 220 V

According to Ohm’s law,

V = IR

R = V/ I = 220/5 = 44Ω

Now for x number of resistors of resistance 176 Ω, the equivalent resistance of the resistors connected in parallel is 44 Ω.

1/44 = 1/176 + 1/176 + 1/176 .....χ times

1/44 = x / 176

=> x = 176/ 44

=> x = 4

Therefore, 4 resistors of 176 Ω are required to draw the given amount of current.

I hope, this will help you___❤❤

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