How many 176 resistors (in parallel) are required to carry 5A on a 220 V line?
Answers
Answered by
22
Resistance in the circuit should be
R = V / i
= 220 V / 5 A
= 44 Ω
Equivalent resistance of “n” resistors each of resistance R’ arranged in parellel is given by
R = R’ / n
From above
n = R’ / R
= 176 Ω / 44 Ω
= 4
∴ 4 resistors are required in the circuit.
R = V / i
= 220 V / 5 A
= 44 Ω
Equivalent resistance of “n” resistors each of resistance R’ arranged in parellel is given by
R = R’ / n
From above
n = R’ / R
= 176 Ω / 44 Ω
= 4
∴ 4 resistors are required in the circuit.
adityatiwari9644:
good job
1 no
Answered by
14
The resistance given when 5A electric current flows with 220V line is -->
R = V ÷ I
R = 220 ÷ 5
R = 44 ohm
Given resistance - 176 ohm
n x 44 = 176
where n = number of resistors required.
n = 176 ÷ 44
n = 4
Hence your required answer is 4
Hope This Helps You!
R = V ÷ I
R = 220 ÷ 5
R = 44 ohm
Given resistance - 176 ohm
n x 44 = 176
where n = number of resistors required.
n = 176 ÷ 44
n = 4
Hence your required answer is 4
Hope This Helps You!
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