How many 176ohm resistors are required to carry 5A on a220 volt line
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given,
i= 5 A
v= 220V
we know V=IR
=> R=V/I
=220/5
= 44 ohm
now, R= R/n
44= 176/n
=> n =176/44
=> n= 4
required no. of resistor = 4
i= 5 A
v= 220V
we know V=IR
=> R=V/I
=220/5
= 44 ohm
now, R= R/n
44= 176/n
=> n =176/44
=> n= 4
required no. of resistor = 4
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