Math, asked by gangwar92, 11 months ago

How many 2's are there in cube of 1?​

Answers

Answered by sam3255
2

The numbers 729, 1000, 1728 are also perfect cubes. We note that 1 = 1 × 1 × 1 = 13; 8 = 2 × 2 × 2 = 23; 27 = 3 × 3 × 3 = 33. Since 53 = 5 × 5 × 5 = 125, therefore 125 is a cube number.

Answered by throwdolbeau
0

Answer:

Number of 2's present in the cube of 1 = 0

Step-by-step explanation:

Cube of any number states that the number is multiplied by itself three times

⇒ Cube means that the number is raised to the power of 3

Now, we will find the cube of 1

So, Cube of 1 = 1 × 1 × 1

⇒ Cube of 1 = 1³

⇒ Cube of 1 = 1

Now, we need to find the number of 2's in the cube of 1

As, Cube of 1 contains only one digit that is 1

So, there is no 2 present in t he cube of 1

Therefore, Number of 2's present in the cube of 1 = 0

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