How many 2's are there in cube of 1?
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The numbers 729, 1000, 1728 are also perfect cubes. We note that 1 = 1 × 1 × 1 = 13; 8 = 2 × 2 × 2 = 23; 27 = 3 × 3 × 3 = 33. Since 53 = 5 × 5 × 5 = 125, therefore 125 is a cube number.
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Answer:
Number of 2's present in the cube of 1 = 0
Step-by-step explanation:
Cube of any number states that the number is multiplied by itself three times
⇒ Cube means that the number is raised to the power of 3
Now, we will find the cube of 1
So, Cube of 1 = 1 × 1 × 1
⇒ Cube of 1 = 1³
⇒ Cube of 1 = 1
Now, we need to find the number of 2's in the cube of 1
As, Cube of 1 contains only one digit that is 1
So, there is no 2 present in t he cube of 1
Therefore, Number of 2's present in the cube of 1 = 0
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