how many 2digit no. s are divisible by 3
Answers
Answered by
77
Hola there,
To find two digit no. divisible by 3
A.P. = 12, 15,.........99
a = 12
an = 99
d = 15 - 12 = 3
=> an = a + (n - 1)d
=> 99 = 12 + (n - 1)3
=> n - 1 = 87/3
=> n - 1 = 29
=> n = 30
So, 30 two digit no. are divisible by 3.
Hope this helps....:)
To find two digit no. divisible by 3
A.P. = 12, 15,.........99
a = 12
an = 99
d = 15 - 12 = 3
=> an = a + (n - 1)d
=> 99 = 12 + (n - 1)3
=> n - 1 = 87/3
=> n - 1 = 29
=> n = 30
So, 30 two digit no. are divisible by 3.
Hope this helps....:)
Answered by
4
let .a.p be .......12, 15........99
first we have to find common difference that is d= a2-a1
=15-12
=3
we know that general formula
99=12+(n-1)×3
= 12+3n-3
=9+3n
99-9=3n
90/3=n
n= 30
there fore 30 numbers
first we have to find common difference that is d= a2-a1
=15-12
=3
we know that general formula
99=12+(n-1)×3
= 12+3n-3
=9+3n
99-9=3n
90/3=n
n= 30
there fore 30 numbers
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