Question

how many 2digit numbers are their which leave remainder 2 on division by 3
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Answer 1

Answer:

There are 29 two digit numbers which leave remainder 2 on division by 3

Step-by-step explanation:

The required sequence will be 14, 17 ,20 etc.upto 98

The first term a=14

The last term l=98

common difference=3

general term of AP is

l=a+(n-1)d

98 =14+(n-1)3

98-14=3n-3

84+3=3n

n=29