How many 3-digit natural numbers are divisible. by 3 and not 7?
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0
Answer:
,,112,115,102,105,108
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2
Answer:
no. divisible by both 3 and 7 will be multiple of 21 which will be 43 digits
no. divisible by 3 is series of AP
where a= 102 d= 3 l= 999
l=a +(n-1)d
999=102+(n-1)3
333-34= n-1
299+1=n
n=300
300-43=217digits
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