How many 3-digit non-negative numbers are there that have remainder 7 when divided by 101? Here we assume that 1-digit and 2-digit numbers are also 3-digit, they just start with 0.
Answers
Answered by
0
Answer:
I don't
Step-by-step explanation:
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ans
Answered by
3
Answer:
10
Step-by-step explanation:
The breakdown to get a remainder of 7 is:
(101 * x) + 7
We are good as long as we keep that total under 1000 so x can range from 0 to 9
(101 * 0) + 7 = 7
(101 * 9) + 7 = 916
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