How many 3 digit number can be formed using the digits 1 to 9 if no digit is repeated.
From Permutation nd Combination Chapter.
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How many 3 digit number can be formed using the digits 1 to 9 if no digit is repeated?
Good question,
Here is your perfect answer!
Here n = 9,
r = 3
Then total three digit numbers
= 9
A
3
= 9!/(9-6)!
= 9!/6!
= 9*8*7*6!/6!
= 504.
Good question,
Here is your perfect answer!
Here n = 9,
r = 3
Then total three digit numbers
= 9
A
3
= 9!/(9-6)!
= 9!/6!
= 9*8*7*6!/6!
= 504.
kissan9:
thnku
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