How many 3 digit numbers can be made with 1,5,4,6,7 which are completely divisible by 6?
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AP=102,108,114.............996
a=102
d=6
an=996
n=?
an=a+(n-1)×d
996=102+(n-1)×6
996=102+6n-6
996=96+6n
996-96=6n
900=6n
900÷6=n
n=150
a=102
d=6
an=996
n=?
an=a+(n-1)×d
996=102+(n-1)×6
996=102+6n-6
996=96+6n
996-96=6n
900=6n
900÷6=n
n=150
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