Question

How many 6 digit numbers can be formed using the digits 0 to 5 without repetition such that?

Answer 1

◆ Permutation n Combinations ◆

Hey !!

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Answer 2

hey!
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the first digit can be 0.
If the one’s digit is one of 1, 2, 5, the number is already divisible by 1, 2, 3 or 5 respectively.
So far we have a total of 4x4x4!=384 possibilities.
If the one’s digit is 4, the tens digit can be 0 or 2 giving 4!+3x3!=42 more possibilities.

=>384+42=426
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