How many 6 digit numbers can be formed using the digits 0 to 5 without repetition such that?
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Answered by
7
◆ Permutation n Combinations ◆
Hey !!
Check the attachment.
Hope it helps you :)
Hey !!
Check the attachment.
Hope it helps you :)
Attachments:
TheAishtonsageAlvie:
u understood all of us as a teacher :D
Answered by
0
hey!
...
the first digit can be 0.
If the one’s digit is one of 1, 2, 5, the number is already divisible by 1, 2, 3 or 5 respectively.
So far we have a total of 4x4x4!=384 possibilities.
If the one’s digit is 4, the tens digit can be 0 or 2 giving 4!+3x3!=42 more possibilities.
=>384+42=426
.....
thank u
hope it helps u
...
the first digit can be 0.
If the one’s digit is one of 1, 2, 5, the number is already divisible by 1, 2, 3 or 5 respectively.
So far we have a total of 4x4x4!=384 possibilities.
If the one’s digit is 4, the tens digit can be 0 or 2 giving 4!+3x3!=42 more possibilities.
=>384+42=426
.....
thank u
hope it helps u
(:-)
Can you explain about that divisible thing ...
Why you took so, it's nowhere given
ok
even I got the answer as 600 but I checked on net I felt the method was easy so I just posted the answer from net and I will explain u in easy method
The solution you've posted seems to be that of a different question
no it is a same question...
Check once yourself , your answer is wrong dear
OK lev it tomorrow I will solve clearly if I didnot get then report my answer
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