how many 3 digits natural numbers are divisible by 7
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Step-by-step explanation:
3 digit natural numbers are 102,105,108........999
here a=102 and d= 3
tn=999
tn=a+(n-1)d
999=102+(n-1)3
999= 102-3+3n
999=99+3n
999-99=3n
900=3n
n= 300
hence there are 300 natural no. divisible by 3 by this u can solve above
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