How many 3 digits numbers are divisible by 7
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2
Answer:
128
Step-by-step explanation:
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1
Answer:
First 3 digit no. divisible by 7 = 105
Second number = 112
Third number = 119
Last number = 994
The list of 3 digit nos. divisible by 7 are:
105, 112, 119…………… 994
This forms an AP.
a = 105
d = 7
n = 999
⇒ n term = a+(n-1)d
994 = 105 + (n-1)7
994 = 105 + 7n-7
994-105 = 7n-7
889 = 7n-7
889+7 = 7n
896 = 7n
896/7 = n
128 = n
⇒ There are ‘128’ 3-digit numbers divisible by 7.
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