Question

How many 3-letter words with or without meaning, can be formed out of the letters of the word, 'LOGARITHMS', if repetition of letters is not allowed?
answer me guys

Answer 1

10P3=10×9×8=720.........

Answer 2

Answer:

Hey! Sorry for answering here...

Here's the answer to your latest question: 48

Step-by-step explanation:

The given word contains 5 different letters.

Keeping the vowels UE together, we suppose them as 1 letter.

Then, we have to arrange the letters JDG (UE).

Now, we have to arrange in 4! = 24 ways.

The vowels (UE) can be arranged among themselves in 2 ways.

∴ Required number of ways = (24 × 2) = 48

Hey! Hope this helped you. ☺