How many 4 digit number can be formed using 1,2,3,4,5,6,7 with none of digits being replaced?
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hey buddy here is your answer
according to permutation and combination we can do it .
==> we have to make 4 digit number without repetition
==> for this we got (_ _ _ _ ) space to fill
for first space we can fill it by 7 ways because we got all 7 numbers to fill
So 7 ways for first
and for second space we got 6 ways because 1 of 7 numbers we already used of first space so no repetition we got only 6 ways for second space
same for 3rs space we got only 5 choices to make .
so 5 ways for 3rd space
and for last space we got only 4 numbers so only 4 ways for last space
===> in the last total ways for all four spaces is = multiply all possible ways for each space
===> 7(1 space)*6(2nd space )*5(3rd space )*4(4th space = 840 ways ( answer)
there are total 840 ways to fill 4 blanks without repetition
----hope it helps--- ask me if you still got confusion
-- all the best ✌️✌️
according to permutation and combination we can do it .
==> we have to make 4 digit number without repetition
==> for this we got (_ _ _ _ ) space to fill
for first space we can fill it by 7 ways because we got all 7 numbers to fill
So 7 ways for first
and for second space we got 6 ways because 1 of 7 numbers we already used of first space so no repetition we got only 6 ways for second space
same for 3rs space we got only 5 choices to make .
so 5 ways for 3rd space
and for last space we got only 4 numbers so only 4 ways for last space
===> in the last total ways for all four spaces is = multiply all possible ways for each space
===> 7(1 space)*6(2nd space )*5(3rd space )*4(4th space = 840 ways ( answer)
there are total 840 ways to fill 4 blanks without repetition
----hope it helps--- ask me if you still got confusion
-- all the best ✌️✌️
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