How many 4 digit number can made using 1,2,3,4,5,6 and 7 with none of?
Answers
Answered by
2
This is a question on Permutations where order matters.
No of 4 digit numbers that can be formed using 1,2,3,4,5,6 & 7 where none of digits is repeated is denoted by P(7,4)
P(7,4) = 7!/3! =7 x 6 x 5 x 4 = 840
For that matter, this answer is valid for any 7 distinct digits except 0.
Similar questions