Question

How many 4 digit numbers are there without repetition of digits if each number is divisible by 5....

Which whole explanation.....

I will mark him as BRAINLIEST.......

Answer 1

If a number is divisible by 5, then it's last digit must be 0 or 5. So let's take 2 cases.

1st case: 4 digit Number ending with 0.

By the method of permutation and combination,

The unit place can be filled with only 1 number that's 0.

The tens place can be filled with remaining 9 numbers.

The hundreds place can be filled with remaining 8 numbers(which excludes 0 and tens digit)

The thousands place can be filled with remaining 7 numbers (which excludes 0, tens digit and hundreds digit).

So total numbers formed are 9*8*7*1 = 504

2nd case: 4 digit Number ending with 5.

The unit place can be filled with only 1 number that's 5.

The thousands place can be filled with remaining 8 numbers ( excludes 0 and 5 )

The hundreds place can be filled with remaining 8 numbers(which excludes thousands digit and 5)

The tens place can be filled with remaining 7 numbers ( which excludes thousands hundreds digit and 5).

So total numbers formed 8*8*7*1= 448

Hence the total numbers are 504 + 448 = 952

Answer 2

Step-by-step explanation:

$\huge\blue{Above answer is correct}$