Question

The base of a right angle triangle measures 4 cm and its hypotenuse measure 5 cm . Find the area of the triangle .

Answer 1

Here, we are given that


Base = 4cm
Hypotenuse = 5cm


Area of a triangle = 1/2 × base × height.


Height is not given

In a right triangle, the height is the third side apart from base and hypotenuse. So by Pythagoras Theorem, we can find the third side . We know that,


h² = b² + p²

Where h = hypotenuse, b = base and p = perpendicular (height)

So, p² = h² - b²

=> p² = 5² - 4²

=> p² = 25 - 16

=> p² = 9

=> p = √9

=> p = 3cm

So the perpendicular (height) is 3 cm

So area = 1/2 × base × height


=> 1/2 × 4 × 3

=> 2 × 3

= 6 cm²


Your answer :- 6 cm²


Hope it helps dear friend ☺️✌️✌️

Answer 2

Here is your solution

Given that :-

The base of a right angle triangle measures 4 cm

Hypotenuse = 5 cm.

Firstly we will find height (p) of triangle

$h {}^{2} = p {}^{2} + b {}^{2} \\ 5 {}^{2} = p {}^{2} + 4 {}^{2} \\ 5 {}^{2} - 4 {}^{2} = p {}^{2} \\ 25 - 16 = p {}^{2} \\ p = \sqrt{9} \\ p = + - 3$

Area of triangle =1/2×b×h

Area of triangle=>1/2×4×3

Area of triangle=>6cm^2

Hope it helps you