Let S be the set of all ordered pairs (x,y) of positive integers, with HCF (x,y)= 16 and LCM(x,y) = 48000. The number of elements in set A is
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48000 = 16 × 3000
= 16 × [3^1× 2^3 × 5^3)
As H.C.F. is 16 So 2^3 can be selected in 1 way & 3^1 × 5^3 can be seleted in (1+ 1) (3 +1) = 8 ways
No of ordred pairs = 8
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