Question

how many 4 digit numbers can be formed using the digits 1,2,3,7,8,9.

a)how many of these are less than 6000

b)how many of these end with 7

Answer 1

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$\huge{ \green{ \: answer}} >$In how many ways 4-digit numbers can be formed using the digits 1, 2, 3, 7, 8, and 9 without repetition? How many of these are even numbers?

6P4 = 6!/(6 - 4)! = 720/2 = 360

Second method:

6 x 5 x 4 x 3 = 36

The even number solutions end in either 2 or 8. So there are only two possible last digits.

The three digits preceding give 5 x 4 x 3 = 60 solutions. Including the last digits give us:

60 x 2 = 120








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