Question

how many 440 ohms resistor in parallel are required to carry
current of 5 ampere in a 220 volt line

Answer 1

Given:

Many 440 ohm resistances had placed in parallel combination in a 220 volt line.

To find:

Number of resistors required to carry a current of 5 ampere .

Calculation:

Let n of resistors be required.

Hence , equivalent resistance of the circuit will be :

$\therefore \: \dfrac{1}{R_{eq}} = \dfrac{1}{440} + \dfrac{1}{440} + ...... + \: n \: times$

$= > \: \dfrac{1}{R_{eq}} = \dfrac{n}{440}$

$= > \: R_{eq} = \dfrac{440}{n}$

Now , required current through the circuit is 5 Amperes.

$\therefore \: 5 = \dfrac{220}{R_{eq}}$

$= > \: 5 = \dfrac{220}{( \frac{440}{n} )}$

$= > \: 5 = \dfrac{n}{2}$

$= > \: n = 10 \: \: resistors$

So , final answer is :

10 resistors are required.

Answer 2

n = 10 resistor

10 resistors are required.