Math, asked by LUCKYRACER9598939, 9 months ago

How many 5-digit telephone numbers can be constructed using the digits 0 to 9 if each number starts with 67 and no digit appears more than once?​

Answers

Answered by ITZINNOVATIVEGIRL588
11

━━━━━━━━━━━━━━━━━━━━━━━━━

\Large\fbox{\color{purple}{QUESTION}}

How many 5-digit telephone numbers can be constructed using the digits 0 to 9 if each number starts with 67 and no digit appears more than once?

━━━━━━━━━━━━━━━━━━━━━━━━━

\bf\Huge\red{\mid{\overline{\underline{ ANS</p><p>WER }}}\mid }

➡️Let the five-digit number be ABCDE. Given that first 2 digits of each number is 67. Therefore, the number is 67CDE.

➡️As the repetition is not allowed and 6 and 7 are already taken, the digits available for place C are 0,1,2,3,4,5,8,9. The number of possible digits at place C is 8. Suppose one of them is taken at C, now the digits possible at place D is 7. And similarly, at E the possible digits are 6.

➡️∴The total five-digit numbers with given conditions = 8 × 7 × 6 = 336.

\Large\mathcal\green{FOLLOW \: ME}

━━━━━━━━━━━━━━━━━━━━━━━━━

Answered by Rudranil420
26

Answer:

➡️Let the five-digit number be ABCDE. Given that first 2 digits of each number is 67. Therefore, the number is 67CDE.

➡️As the repetition is not allowed and 6 and 7 are already taken, the digits available for place C are 0,1,2,3,4,5,8,9. The number of possible digits at place C is 8. Suppose one of them is taken at C, now the digits possible at place D is 7. And similarly, at E the possible digits are 6.

➡️∴The total five-digit numbers with given conditions = 8 × 7 × 6 = 336.✔

Step-by-step explanation:

HOPE IT HELP YOU ✌✌

Similar questions