how many 5 digits numbers have the sum of their digits greater than 45?
Answers
Answered by
4
Answer:
Step-by-step explanation:
So the digit sum will be even when X=1,3,5,7,9, and odd when X = 0,2,4,6,8. Hence, the answer is (99,999–9,999)/2 = 45,000.
Answered by
5
Answer:
0
Step-by-step explanation:
Smallest five digit number is 10000
Largest five digit number is 99999
The sum of largest 5 digit number 9+9+9+9+9=45.
So answer is 0
Similar questions