Math, asked by Anonymous, 3 months ago

How many 5 digits telephone numbers can be constructed using the digit 0 to 9 if each number start with 67 and no digits appear more than once.​

Answers

Answered by Smdkaif7860
7

Answer:

It is given that the 5-digit telephone numbers always start with 67.

Therefore, there will be as many phone numbers as there as ways of filling 3 vacant places by the digits 0-9, keeping in mind that the digits cannot be repeated.

The unit place can be filled by any of the digits from 0-9, expect digits 6 and 7.

Therefore, the unit place can be filled in 8 different ways following which, the tens place can be filled in by any of the remaining 7 digits in 7 different ways, and the hundreds place can be filled in by any of the remaining 6 digits in 6 different ways.

Therefore, by the multiplication principle, the required number of ways in which 5- digit telephone numbers can be constructed is 8×7×6=336

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